4.905t^2-59t+118=0

Solution for 4.905t^2-59t+118=0 equation:

4.905t^2-59t+118=0

a = 4.905; b = -59; c = +118;
Δ = b2-4ac
Δ = -592-4·4.905·118
Δ = 1165.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{1165.84}}{2*4.905}=\frac{59-\sqrt{1165.84}}{9.81}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{1165.84}}{2*4.905}=\frac{59+\sqrt{1165.84}}{9.81}
$